Printing sum of two square using For Loop in C++

This C++ program calculates the sum of the squares of numbers from 1 to a given limit n and prints the total value. Here is how the program works:

The program starts by including the necessary header file iostream and using the namespace std.
The program declares four integer variables: i, j, and n. i and j are initialized to 0, and n is input by the user.
The program then enters a for loop that runs from i=1 to i=n. In each iteration of the loop, the value of i is squared and added to the current value of j.
After the loop finishes, the total value of j is printed as output.
The program returns 0, indicating successful execution.

Source Code

#include<iostream>
using namespace std;
int main()
{
    int i,j=0,n;
    cout<<"\nEnter the Limit:";
    cin>>n;
    for(i=1;i<=n;i++)
    {
        j=i*i+j;
    }
    cout<<"\nTotal value is:"<<j;
    return 0;
}

To download raw file Click Here

Output

Enter the Limit:4
Total value is:30

Program List

Flow Control

IF Statement Examples

Switch Case

Goto Statement

Break and Continue

While Loop

Do While Loop

For Loop

Friend Function in C++

String Examples

Array Examples

Structure Examples

Structure & Pointer Examples

Structure & Functions Examples

Enumeration Examples

Template Examples

Functions

Inheritance Examples

Hierarchical Inheritance

Hybrid Inheritance

Multiplication using Hybrid Inheritance

Multilevel Inheritance

Multiple Inheritance

Single Level Inheritance

Class and Objects

Constructor Example

Destructor Example

Destructor Example in C++

Operator Overloading Example

Operator and Function Example

Display Values using Friend Function

List of Programs

Pointer Examples

Memory Management Examples

Pointers and Arrays

Virtual Function Examples