Priniting continues numbers using break and continue in C++

This C++ program uses a for loop to iterate from 0 to 9 (inclusive) and print the values of the loop variable i, except when i equals 4. When i equals 4, the loop is exited prematurely using the break statement. Here's a breakdown of the program's logic:

The program starts executing from the main() function.
A for loop is used to iterate from 0 to 9 (inclusive).
For each iteration of the loop, the value of the loop variable i is printed to the console using cout.
If the value of i equals 4, the loop is exited prematurely using the break statement.
After the loop is exited, the program returns 0 to indicate successful completion.

Source Code

#include<iostream>
using namespace std;
int main()
{
    for(int i=0;i<10;i++)
    {
        if (i==4)
        {
            break;
        }
        cout<<i<<"\n";
    }
    return 0;
}

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Output

012356789

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