Find Vowels using Switch Case in C++

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This C++ program takes an input of an alphabet and uses a switch statement to check whether the entered alphabet is a vowel or not. Here's how the program works:

• The program prompts the user to enter an alphabet.
• The user enters a single alphabet in lower case.
• The program uses a switch statement to check which alphabet was entered.
• If the entered alphabet is one of 'a', 'e', 'i', 'o', or 'u', the program outputs that it is a vowel alphabet.
• If the entered alphabet is not one of these, the program outputs that it is not a vowel.
• The break statement is used to end each case statement and prevent the program from executing subsequent case statements.
• Finally, the program returns 0 to indicate successful execution.

Overall, this program is a good example of how to use a switch statement in C++ to handle multiple cases. However, it could be improved by adding input validation to check that the entered input is a valid lower case alphabet. Additionally, it could be modified to handle upper case alphabets as well by converting the entered alphabet to lower case before checking for vowel status.

Source Code

#include<iostream>
using namespace std;
int main()
{
    char x;
    cout<<"\nEnter the alphabet :";
    cin>>x;
        switch(x)
        {
            case 'a':
            case 'e':
            case 'i':
            case 'o':
            case 'u':
                cout<<"\n"<<x<<" is a vowel alphabet";
                break;
            default:
                cout<<"\n"<<x<<"\n is not a vowel";
                break;
        }
    return 0;
}

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Output

Enter the alphabet :e
e is a vowel alphabet

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