Printing odd and even numbers using For Loop in C++

This C++ program prompts the user to enter an ending value and then displays all the even and odd numbers up to that value, along with their counts. Here's how the program works:

It first declares some variables, including i for the loop counter, n to store the user input, even to count the even numbers, and odd to count the odd numbers.
It then prompts the user to enter an ending value and reads the input using cin.
It then displays all the even numbers up to the input value by looping through all integers from 0 to n and checking if each one is even using the modulo operator (%). If it's even, it prints the number and increments the even counter.
It then displays all the odd numbers up to the input value by looping through all integers from 1 to n and checking if each one is odd using the modulo operator (%). If it's odd, it prints the number and increments the odd counter.
Finally, it displays the total counts of even and odd numbers.

Source Code

#include<iostream>
using namespace std;
int main()
{
    int i,n,even=0,odd=0;
    cout<<"\nEnter the Ending value:";
    cin>>n;
    cout<<"\nEven numbers:";
    for(i=0;i<=n;i++)
    {
        if(i%2==0)
        {
            cout<<"\n"<<i;
            even++;
        }
    }
    cout<<"\nOdd numbers:";
    for(i=1;i<=n;i++)
    {
        if(i%2==1)
        {
            cout<<"\n"<<i;
            odd++;
        }
    }
    cout<<"\nTotal even numbers:"<<even;
    cout<<"\nTotal odd numbers:"<<odd;
    return 0;
}

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Output

Enter the Ending value:10
Even numbers:
0
2
4
6
8
10
Odd numbers:
1
3
5
7
9
Total even numbers:6
Total odd numbers:5

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