Printing square pattern outline using For Loop in C++

This is a C++ program that uses loops to print a square pattern of stars. The pattern is printed in a single loop. Here is an explanation of how the program works:

The program first declares three integer variables - i, j, and n.
The user is prompted to enter a value for n.
The program enters a loop that iterates n times. This loop is responsible for printing the rows of the square.
Within the loop, there is another loop that iterates n times. This loop is responsible for printing the columns of the square.
For each element in the square, the program checks whether it is on the border or not. If the element is on the border (i.e., if i is equal to 1 or n, or if j is equal to 1 or n), then a star is printed. Otherwise, a space is printed.
The program then exits the loop and the main() function, returning 0.
The square pattern is printed to the console.

Source Code

#include<iostream>
using namespace std;
int main()
{
    int i,j,n;
    cout<<"\nEnter the value:";
    cin>>n;
    for(i=1;i<=n;i++)
    {
        cout<<"\n";
        for(j=1;j<=n;j++)
        {
            if(i==1||i==n||j==1||j==n)
                cout<<" *";
            else
                cout<<"  ";
        }
    }
    return 0;
}

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Output

Enter the value:10
 * * * * * * * * * *
 *                 *
 *                 *
 *                 *
 *                 *
 *                 *
 *                 *
 *                 *
 *                 *
 * * * * * * * * * *

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