Printing formula examples using For Loop in C++

Example Program 1

This program calculates the sum of the series 1/1! + 2/2! + 3/3! + ... + n/n!. The program starts by initializing four variables: i, j, n, and fact. j and fact are initialized to 0 and 1 respectively. The program then prompts the user to enter the value of n.

In the for loop, the program calculates the factorial of each number from 1 to n and stores it in fact. It then calculates the value of i/fact and adds it to j. This is repeated for each value of i from 1 to n. Finally, the program prints out the value of j, which is the sum of the series.

Source Code

#include<iostream>
using namespace std;
int main()
{
    float i,j=0,n,fact=1;
    cout<<"\nEnter the limit:";
    cin>>n;
    for(i=1;i<=n;i++)
    {
        fact=fact*i;
        j=j+i/fact;
    }
    cout<<"\nTotal value:"<<j;
    return 0;
}

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Output

Enter the limit:5
Total value:2.70833

Example Program 2

This program calculates the sum of the series 1 + 1/2 + 1/3 + ... + 1/n. The program starts by initializing two variables: i and j. j is initialized to 0. The program then prompts the user to enter the value of n.

In the for loop, the program calculates the value of 1/i for each value of i from 1 to n and adds it to j. This is repeated for each value of i. Finally, the program prints out the value of j, which is the sum of the series.

Source Code

#include<iostream>
using namespace std;
int main()
{
    float i,j=0,n;
    cout<<"\nEnter the limit:";
    cin>>n;
    for(i=1;i<=n;i++)
    {
        j=j+1/i;
    }
    cout<<"\nTotal value:"<<j;
    return 0;
}

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Output

Enter the limit:5
Total value:2.28333

Example Program 3

This program calculates the sum of the series 1/1 + 1/3 + 1/5 + ... + 1/n. The program starts by initializing two variables: i and j. j is initialized to 0. The program then prompts the user to enter the value of n.

In the for loop, the program calculates the value of 1/i for each odd value of i from 1 to n and adds it to j. This is repeated for each odd value of i. Finally, the program prints out the value of j, which is the sum of the series.

Source Code

#include<iostream>
using namespace std;
int main()
{
    float i,j=0,n;
    cout<<"\nEnter the limit:";
    cin>>n;
    for(i=1;i<=n;i=i+2)
    {
        j=1/i+j;
    }
    cout<<"\nTotal value:"<<j;
    return 0;
}

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Output

Enter the limit:5
Total value:1.53333

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