Print values divisible by 7 using One Dimensional Array in C

This program is written in C programming language and it does the following:

It first declares some integer variables i, j, n and an array a
The program then prompts the user to enter a limit 'n' which determines the size of an integer array 'a'
Then, it prompts the user to enter 'n' values which are stored in the array 'a'
Next, it prints the given values by using a for loop to iterate through the array
Then it uses another for loop to check each element of the array 'a' and check if the element is divisible by 7 or not by using the modulus operator(%)
If the element is divisible by 7 it prints the element using printf statement and increments the value of j
Finally, it prints the total number of elements divisible by 7 using printf statement
The program ends by returning 0 as the value of the main function.

Source Code

#include<stdio.h>
int main()
{
  int i,j=0,n,a[10];
  printf("\nEnter the Limit:");
  scanf("%d",&n);
  printf("\nEnter the Values:");
  for(i=0;i<n;i++)
  {
    scanf("%d",&a[i]);
  }
  printf("\nGiven values are:");
  for(i=0;i<n;i++)
  {
     printf("\na[%d]=%d",i,a[i]);
  }
  printf("\nNumbers divisible by 7:");
  for(i=0;i<n;i++)
  {
      if(a[i]%7==0)
      {
         printf("\na[%d]=%d",i,a[i]);
         j++;
      }
  }
  printf("\nTotal numbers divisible by 7=%d",j);
  return 0;
}

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Output

Enter the Limit:5
Enter the Values:1
7
28
4
35
Given values are:
a[0]=1
a[1]=7
a[2]=28
a[3]=4
a[4]=35
Numbers divisible by 7:
a[1]=7
a[2]=28
a[4]=35
Total numbers divisible by 7 =3

Print values divisible by 7 using One Dimensional Array in C

Source Code

Output

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