Pairs of distinct elements and their character position sum from two lists
Creates a dictionary called char_pos_sum_dict using a dictionary comprehension in Python. This dictionary maps pairs of strings from two lists, list1 and list2, to the sum of the ordinal values (ASCII values) of the characters in each pair. Here's a step-by-step explanation of the code:
- list1 = ["abc", "def", "ghi"]: This line defines a list called list1 containing three strings.
- list2 = ["jkl", "mno", "pqr"]: This line defines another list called list2 containing three strings.
- char_pos_sum_dict = {(x, y): sum(ord(char) for char in x) + sum(ord(char) for char in y) for x in list1 for y in list2}: This line creates the char_pos_sum_dict dictionary using a nested dictionary comprehension. Here's how it works:
- {(x, y): sum(ord(char) for char in x) + sum(ord(char) for char in y) for x in list1 for y in list2} is the dictionary comprehension. It iterates over pairs of strings (x, y) where x comes from list1 and y comes from list2.
- For each pair of strings, it creates a key-value pair in the dictionary. The key x, y is a tuple containing the two strings. The value is calculated by summing the ordinal values (ASCII values) of all characters in the first string x and all characters in the second string y.
- print(list1): This line prints the contents of list1 to the console.
- print(list2): This line prints the contents of list2 to the console.
- print(char_pos_sum_dict): This line prints the char_pos_sum_dict dictionary to the console.
Source Code
list1 = ["abc", "def", "ghi"]
list2 = ["jkl", "mno", "pqr"]
char_pos_sum_dict = {(x, y): sum(ord(char) for char in x) + sum(ord(char) for char in y) for x in list1 for y in list2}
print(list1)
print(list2)
print(char_pos_sum_dict)
Output
['abc', 'def', 'ghi']
['jkl', 'mno', 'pqr']
{('abc', 'jkl'): 615, ('abc', 'mno'): 624, ('abc', 'pqr'): 633, ('def', 'jkl'): 624, ('def', 'mno'): 633, ('def', 'pqr'): 642, ('ghi', 'jkl'): 633, ('ghi', 'mno'): 642, ('ghi', 'pqr'): 651}