Sorting Integers with Varargs in Java

Create a Java program to demonstrate a method with varargs that sorts a sequence of integers

The class SortNumbers contains a single static method sortNumbers that takes a variable number of integers as input (using varargs).
Inside the sortNumbers method, it first prints the given numbers using Arrays.toString(numbers).
It then sorts the numbers array using Arrays.sort(numbers), which sorts the array in ascending order.
After sorting, it prints the sorted numbers using Arrays.toString(numbers).
In the main method, the sortNumbers method is called with a list of integer values to demonstrate its functionality.

Source Code

import java.util.Arrays;
 
public class SortNumbers
{
	static void sortNumbers(int... numbers)
	{
		System.out.println("Given Numbers : " + Arrays.toString(numbers));
		Arrays.sort(numbers);
		System.out.println("Sorted Numbers : " + Arrays.toString(numbers));
	}
 
	public static void main(String[] args)
	{
		sortNumbers(80, 73, 65, 15, 39, 51);
	}
}

Output

Given Numbers : [80, 73, 65, 15, 39, 51]
Sorted Numbers : [15, 39, 51, 65, 73, 80]

Sorting Integers with Varargs in Java

Source Code

Output

Example Programs

Method with Varargs Programs in Java