Count Even Numbers with Varargs in Java

Write a Java program to find the count of even numbers in a sequence using varargs

The class contains a method called countEvenNumbers, which takes a variable number of integers as input. Inside this method, it iterates through each number in the input array and checks if it's even (divisible by 2 with no remainder). If a number is even, it increments a counter.

The main method is the entry point of the program. Inside main, it calls the countEvenNumbers method with a list of numbers from 1 to 10 as arguments. It stores the result, which is the count of even numbers, in a variable named count.

Finally, it prints out the result using System.out.println, displaying "Count of Even Numbers : " followed by the calculated count of even numbers.

Source Code

public class EvenNumberCounter
{
	static int countEvenNumbers(int... numbers)
	{
		int count = 0;
		for (int num : numbers)
		{
			if (num % 2 == 0)
			{
				count++;
			}
		}
		return count;
	}
 
	public static void main(String[] args)
	{
		int count = countEvenNumbers(1, 2, 3, 4, 5, 6, 7, 8, 9 ,10);
		System.out.println("Count of Even Numbers : " + count);
	}
}

Output

Count of Even Numbers : 5